Answer:
Factoring Polynomials
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\sf\bold 1.) \: 4 {x}^{2} - 6x1.)4x
2
−6x
\sf = \boxed{\bold{2x(2x - 3)}}=
2x(2x−3)
\sf\bold 2.) \: c {}^{2} - 92.)c
2
−9
\sf = {c}^{2} - {3}^{2}=c
2
−3
2
\sf = \boxed{\bold{(c - 3)(c + 3)}}=
(c−3)(c+3)
\sf\bold 3) \: {b}^{3} + 273)b
3
+27
\sf = {b}^{3} + {3}^{3}=b
3
+3
3
\sf = (b + 3)( {b}^{2} - b \times 3 + {3}^{2} )=(b+3)(b
2
−b×3+3
2
)
\sf = (b + 3)( {b}^{2} - 3b + {3}^{2} )=(b+3)(b
2
−3b+3
2
)
\sf = \boxed{\bold{(b + 3)( {b}^{2} - 3b + 9) }}=
(b+3)(b
2
−3b+9)
\sf\bold 4) \: {h}^{2} - 10h + 254)h
2
−10h+25
\sf = {h}^{2} - 2 \times h \times 5 + 25=h
2
−2×h×5+25
\sf = {h}^{2} - 2 \times h \times 5 + {5}^{2}=h
2
−2×h×5+5
2
\sf = \boxed{\bold{(h - 5) {}^{2} }}=
(h−5)
2
\sf\bold 5) \: {r}^{2} - r - 125)r
2
−r−12
\sf = {r}^{2} + 3r - 4r - 12=r
2
+3r−4r−12
\sf = r(r + 3) - 4r - 12=r(r+3)−4r−12
\sf = (r + 3) - 4(r + 3)=(r+3)−4(r+3)
\sf = \boxed{\bold{(r + 3)(r - 4)}}=
(r+3)(r−4)
#staysmart;)
Step-by-step explanation:
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