What is the percent by mass concentration of a solution that contains 2.0g sucrose dissolved in 80g water? GIVEN REQUIRED EQUATION SOLUTIONANSWE

Answers 1

Answer:

Getting the percentage concentration is determining the amount of solute (the one dissolved) in a given solution. There are different ways to obtain this, and in the following solution 2g sucrose in 80 grams water, we will use percent concentration by mass (or the mass mass percent concentration)

This is the formula:

Percent by mass (% by mass) = (mass of solute / mass of solution) x 100

Substitute two grams (2g) to the mass of solute and divide it with the mass of the solution (notice that this is usually the formula in getting the concentration of solution problems). The mass of solution is the sum of the mass of solute and the mass of solvent. In this case, it is two grams (2g) sugar added to eighty grams (80g) water. After getting the quotient of the masses of solute and solution it will be multiplied to one hundred (100) which is how to calculate the final concentration of a solution because it symbolizes percent.

Substitution and solution:

% by mass = (2g /[2g +80g]) x 100

= (2g / 82g) x 100

{note: since two same units were divided, the units can already be canceled}

= 0.02439 x 100

= 2.44 % of sugar {this is the final answer}

Explanation:

Hope it helps

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