Melting lead requires 5.50 cal/g. Calculate how many kilojoules are required to melt 1 lb of lead.

Subject:
Chemistry
Author:
troymorrison
Created:
1 year ago

Answers 1

SOLUTION:

Note 1: 1 cal = 4.184 J

Note 2: 1 lb = 453.6 g

Note 3: 1 kJ = 1,000 J

[tex]\begin{aligned} \text{energy} & = \text{1 lb} \times \frac{\text{453.6 g}}{\text{1 lb}} \times \frac{\text{5.50 cal}}{\text{1 g}} \times \frac{\text{4.184 J}}{\text{1 cal}} \times \frac{\text{1 kJ}}{\text{1,000 J}} \\ & \approx \boxed{\text{10.4 kJ}} \end{aligned}[/tex]

Hence, 10.4 kJ of heat are required to melt 1 lb of lead.

[tex]\\[/tex]

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Melting lead requires 5.50 cal/g. Calculate how many kilojoules are required to melt 1 lb of lead.

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Melting lead requires 5.50 cal/g. Calculate how many kilojoules are required to melt 1 lb of lead.

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