Force
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How much force is acting on a 3200 kg delivery truck if it slows down from 80 km/h to 60 km/h in 5s?
Given:
- Initial Velocity - 80 km/h = 22.22 m/s
- Final Velocity - 60 km/h = 16.67 m/s
- Time - 5 s
- Mass - 3 200 kg
Answer & Solution:
Step 1: Let us find first the acceleration
[tex]\sf A=\frac{vf-vi}{t}[/tex]
[tex]\sf A=\frac{16.6 7 \: m/s-22.22 \: m/s}{5 \: s}[/tex]
[tex]\sf A=\frac{-5.55 \: m/s}{5 \: s}[/tex]
[tex]\sf A=-1.11 \: m/s[/tex]
Step 2: Solve for force
[tex]\sf F=ma[/tex]
[tex]\sf F=(3 \: 200 \: kg)(-1.11 \: m/s^2)[/tex]
[tex]\sf F=- 3 \: 552 \: kg.m/s^2[/tex]
[tex]\sf F=\boxed{\bold{-3 \: 552 \: N}}[/tex]
Hence, the force acting on the delivery truck is -3 552 N
#staysmart;)