✒️[tex]\large \bold{ANSWER:} [/tex]
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[tex]\sf{{ 1.\tt\underline{{ \: 3x²+2x=9 }} }}[/tex]
[tex]\sf{{ {3x}^{2} + 2x - 9 = 0 }}[/tex][tex]\sf{{ a =3 , \: b = 2 , \: c = - 9 }}[/tex]
[tex]\sf{{ x = \frac{ - 2 + \sqrt{ {2}^{2} - 4 \times 3 \times ( - 9)} }{2 \times 3} }} \\ \sf{{or}} \\ \sf{{ x = \frac{ - 2 - \sqrt{ {2}^{2} - 4 \times 3 \times ( - 9)} }{2 \times 3} }}[/tex]
[tex]\sf{{ x = \frac{ - 2 + \sqrt{ {2}^{2} - 4 \times 3 \times ( - 9)} }{2 \times 3} }}[/tex]
[tex]\sf{{x = \frac{ - 2 + \sqrt{4 + 4 \times 3 \times 9} }{2 \times 3} }}[/tex]
[tex]\sf{{x = \frac{ - 2 + \sqrt{4 + 108} }{6} }}[/tex]
[tex]\sf{{x = \frac{ - 2 + \sqrt{112} }{6} }}[/tex]
[tex]\sf{{x = \frac{ - 2 \sqrt{ {4}^{2} \times 7 } }{6} }}[/tex]
[tex]\sf{{x = \frac{ - 2 + \sqrt{ {4}^{2} } \times \sqrt{7} }{6} }}[/tex]
[tex]\sf{{x = \frac{ - 2 + 4 \sqrt{7} }{6} }}[/tex]
[tex]\sf{{x = \frac{2 \times ( - 1 + 2 \sqrt{7} }{6} }}[/tex]
[tex]\sf{{x = \frac{ - 1 + 2 \sqrt{7} }{3} }}[/tex]
[tex]\large \rm Final \: Answer:[/tex]
[tex]\large {\boxed{\rm{\color{black}{\sf{{x = \frac{ - 1 + 2 \sqrt{7} }{3} }} \: \sf{{or}} \: \\ {{x = - \frac{ 1 + 2 \sqrt{7} }{3} }} }}}}[/tex]
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[tex]\sf{{2.\tt\underline{{ \: (x-5)(2+3)=7 }}}}[/tex]
[tex]\sf{{ (x - 5) \times 5 = 7 }}[/tex]
[tex]\sf{{ 5x - 25 = 7 }}[/tex]
[tex]\sf{{ 5x = 7 + 25}}[/tex]
[tex]\sf{{ 5x = 32 }}[/tex]
[tex]\large \rm Final \: Answer:[/tex]
[tex]\large {\boxed{\rm{\color{black}{ \sf{{ x = \frac{32}{5} }} }}}}[/tex]
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