Force
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6. A 1000 kg train moving at constant speed is pushed in the opposite direction. If the train decelerated at a rate of 5 m/s², how much force was exerted on the train?
Given:
- Mass - 1 000 kg
- Acceleration - 5 m/s²
Unknown:
Solution:
[tex]\sf F=ma[/tex]
[tex]\sf F=(1000 \: kg)(5 \: m/s^2)[/tex]
[tex]\sf F=5 \: 000 \: kg.m/s^2[/tex]
[tex]\sf F=\boxed{\bold{\red{5000 \: N}}}[/tex]
Therefore, the force of the train is 5000 N
#staysmart;)