Answer:
1. (x−a)(x2+xa+a2)
2. 124u³
3. (x + 4y)(x ^ 2 - 4xy + 16y ^ 2)
4. (2a + b)(4a ^ 2 - 2ab + b ^ 2)
5. (y + 1)(y ^ 2 - y + 1)
Step-by-step explanation:
1. Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2)a3-b3=(a-b)(a2+ab+b2) where a=xa=x and b=ab=a.
(x−a)(x2+xa+a2)
2. Subtract u³ from 125u³
124u³
3. Since both terms are perfect cubes, factor using the sum of cubes formula, a ^ 3 + b ^ 3 = (a + b)(a ^ 2 - ab + b ^ 2) where a = x and b = 4y
(x + 4y)(x ^ 2 - 4xy + 16y ^ 2)
4. Since both terms are perfect cubes, factor using the sum of cubes formula, a ^ 3 + b ^ 3 = (a + b)(a ^ 2 - ab + b ^ 2) where a = 2a
and b = b
(2a + b)(4a ^ 2 - 2ab + b ^ 2)
5. Since both terms are perfect cubes, factor using
the sum of cubes formula, a ^ 3 + b ^ 3 = (a + b)(a ^ 2 - ab + b ^ 2) where a = y and b = 1 .
(y + 1)(y ^ 2 - y + 1)
(brainliest mo ko ha pinaghirapan ko to pagisipan)