Answer:
The standard form is [tex] \rm{3x^2 - 5x - 9 = 0} [/tex] and the values are [tex] \rm{a = 3, \ b = -5, \ c = -9} [/tex].
Step-by-step explanation:
To transform the given equation to standard form, first thing you have to do is expand or use FOIL method. Then subtract both sides of the equation and you will get the standard equation of it.
- [tex] \rm{(x+3)(x-3)=x(4x+5)} \\\\ \rm{x^2 -3^2 = x \cdot 4x + x \cdot 5} \\\\ \rm{x^2 - 9 = 4x^2 + 5x } \\\\ \rm{x^2 - 9 - 5x = 4x^2} \\\\ \rm{-3x^2 - 5x - 9 = 0} [/tex]
As the result shown, we can see that the quadratic term is negative but the rule in the standard form [tex] ax^2 + bx + c = 0 [/tex] is should be positive. To make the quadratic term turn to positive term, just simply multiply it by -1 or divide it by -1. Therefore,
- [tex] \rm{3x^2 - 5x - 9 = 0} [/tex]
Thus, the values are:
- [tex] \rm{a = 3, \ b = -5, \ c = -9} [/tex]
