find the missing terms in each arithmetic sequence _,_,_,8,12,16
Answers 1
Answer:
-4, 0, 4, 8, 12, 16
Step-by-step explanation:
- Simple way:
From the number of the first show (4) to the end (16)
check the interval first
16 - 12 = 4
12 - 8 = 4
we found the interval is 4
so, to find 3 others is by substracted with 4
8 - 4 = 4
4 - 4 = 0
0 - 4 = -4
then we already get the answer:
-4, 0, 4
- Hard way:
find a, a is the arithmetic
find n, n is the sequence
find d, d is the number that first shows up
used this formula:
a n = a 1 + (n - 1) d
d = 4
n = 6 (sequence 6)
a n = a 6
- find a 1 (sequence 1)
a n = a 1 + (6 - 1) 4
a 6 = a 1 + 20
a 6 - a 1 = 20
a 5 = 20
(a).(5) = 20
a = 20/ -5
a = - 4
a could be announced as a 1
we add -4 for sequence 1 =
-4, _, _, 8, 12, 16
- find a 2 (sequence 2)
a n = a 1 + (n - 1) d
d = 4
a1 = -4
n = 2
a 2 = -4 +(2-1)4
a 2 = −4 + (1)(4)
a 2 = −4 + 4
a 2 = 0
add 0 for sequence 2 =
-4, 0, _, 8, 12, 16
- Find a 3 (sequence 3)
d = 4
a 1 = -4
n = 3
a 3 = (-4) + (3 - 1) 4
a 3 = −4 + (2)(4)
a 3 = −4 + 8
a 3 = 4
add 4 for sequence 3 =
-4, 0, 4, 8, 12, 16
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goobercampos
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