Answer:
What is the standard form: 2x (x-3) = 15
2x(x-3) =15
2x²-6x= 15
2x²-6x-15=0
Solve for x: 2x (x-3) = 15
Use quadratic formula:
[tex]x=\frac{-b (+-) \sqrt{b^{2} - 4ac } }{2a}[/tex]
Solution:
a = 2
b = -6
c = -15
[tex]x=\frac{-(6) (+-) \sqrt{(-6)^{2} - 4(2)(-15) } }{2(2)}[/tex]
[tex]x_{1} = \frac{3+\sqrt{39} }{2}[/tex]
[tex]x_{2} = \frac{3-\sqrt{39} }{2}[/tex]
Author:
francishy2w
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6Answer:
DIKO ALM
Step-by-step explanation:
1.2.3.4.5.6.7.8.9.0 DIKO ALM EH SORRY
Author:
sixtopotter
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