1. Which of the following are the factors of 64x2 – 100y??​

Answer:

Pinag mulan ito sa ilalim ng dagat na nag sisilbing plates sa ilalalim ng tubig .Kung kayat Nakaka form ito ng Bulkan .

Answer:

i think letter a.foot spa tool

Answer:

a.foot spa tool

kasi alam Niya naman Kong ana Ang tinatanong aat alam niyo din Kong ano ang sagot Haahahaa

Answer:

Decantation : sand in water

Filtration : Moss and water

Seiving : Water and pebbles

Evaporation : Salt and Water

Magnet : iron filings and sand

To transform rational algebraic expressions to quadratic equations, equate first everything to zero. This might mean changing the sign or operation of the last term after moving it to the left side of the equation. Remove the denominators using the least common denominator. Simplify the equations. Combine the similar terms when necessary.

1. 6x² + 22x + 12
2. x²  - 5x - 10 = 0
3. x² - 2x + 1 = 0

1. [tex]\frac{1}{x}[/tex] + [tex]\frac{x}{2}[/tex] = [tex]\frac{11}{6}[/tex]

Equate everything to zero.

[tex]\frac{1}{x}[/tex] + [tex]\frac{x}{2}[/tex] = [tex]\frac{11}{6}[/tex]

[tex]\frac{1}{x}[/tex] + [tex]\frac{x}{2}[/tex] - [tex]\frac{11}{6}[/tex] = 0

Using the least common denominator, eliminate the denominators of each terms.

(x)(2)(-6)[[tex]\frac{1}{x}[/tex] + [tex]\frac{x}{2}[/tex] - [tex]\frac{11}{6}[/tex] = 0]

(2)(-6)(1) + (x)(-6)(x) - (x)(2)(11) = 0

-12 + (-6x²) - 22x = 0

Write the equation in standard form.

-6x² - 22x - 12 = 0

Remove the negative coefficient of x by multiplying both sides of the equation by -1.

-1[-6x² - 22x - 12 = 0]

6x² + 22x + 12 = 0

2. [tex]\frac{2}{x}[/tex] - [tex]\frac{x - 1}{5}[/tex] = [tex]\frac{-4}{5}[/tex]

Equate everything to zero.

[tex]\frac{2}{x}[/tex] - [tex]\frac{x - 1}{5}[/tex] = [tex]\frac{-4}{5}[/tex]

[tex]\frac{2}{x}[/tex] - [tex]\frac{x - 1}{5}[/tex] + [tex]\frac{4}{5}[/tex] = 0

Using the least common denominator, eliminate the denominators of each terms.

5x [ [tex]\frac{2}{x}[/tex] - [tex]\frac{x - 1}{5}[/tex] + [tex]\frac{4}{5}[/tex] = 0]

(5)(2) - (x)(x - 1) + (x)(4) = 0

10 - x² + x + 4x = 0

Combine the similar terms.

10 - x² + 5x = 0

Write the equation in standard form.

-x² + 5x + 10 = 0

Remove the negative coefficient of x by multiplying both sides of the equation by -1.

-1[-x² + 5x + 10 = 0]

x²  - 5x - 10 = 0

3. [tex]\frac{2}{x - 3}[/tex] + [tex]\frac{x}{2}[/tex] = [tex]\frac{-1}{2}[/tex]

Equate everything to zero.

[tex]\frac{2}{x - 3}[/tex] + [tex]\frac{x}{2}[/tex] = [tex]\frac{-1}{2}[/tex]

[tex]\frac{2}{x - 3}[/tex] + [tex]\frac{x}{2}[/tex] + [tex]\frac{1}{2}[/tex] = 0

Using the least common denominator, eliminate the denominators of each terms.

(x - 3)(2)[[tex]\frac{2}{x - 3}[/tex] + [tex]\frac{x}{2}[/tex] + [tex]\frac{1}{2}[/tex] = 0]

(2)(2) + x(x - 3) + 1(x - 3) = 0

4 + x² -3x + x - 3 = 0

Combine the similar terms.

x² - 2x + 1 = 0

Write the equation in standard form.

x² - 2x + 1 = 0

How to transform algebraic expressions to quadratic equations:

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