750J of work is done in moving a cabinet in a horizontal distance of 7.5m.How much force is used to move the cabinet​

Answers 1

Answer:

F = 100 N

Explanation:

Given:

W = 750 J

d = 7.5 m

F = ?

Solution:

W = Fd

F = W/d

F = 750 J / 7.5m

F = 750 Nm / 7.5m

F = 100 N

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