what is phyical change​

[tex]{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}[/tex]

▪ [tex]\bm{F = force = \: 16 N}[/tex]

▪ [tex]\bm{m= mass = 90 kg}[/tex]

▪ [tex]\bm{t = time = 2 min = 120 s}[/tex]

▪ [tex]\small\bm{Vo = \: initial \: \: velocity = 0 m/s \: ( rest) }[/tex]

[tex]{\large{\textsf{\textbf{\underline{\underline{ Explanation:}}}}}}[/tex]

‣ First, calculate the [tex]\bold{acceleration}[/tex]:-

[tex]\tt{ F = ma}[/tex]

[tex]\tt{a= \dfrac{F}{m} }[/tex]

[tex]\tt{= \dfrac{16 \: kg \cdot \dfrac{m}{ {s}^{2} } }{90kg} }[/tex]

[tex]\tt{ = 0.178 \dfrac{m}{ {s}^{2} }}[/tex]

The final velocity of the body is given by the [tex]\tt{ kinematics \: \: equation}[/tex]:-

[tex]\tt{ v=u+at}[/tex]

[tex]\tt{ = 0 + (0.178 \dfrac{m}{ {s}^{2} } )(120 \: s)}[/tex]

[tex]\boxed{ \red{ \tt{=21.36 \dfrac{m}{s} }}}\large{✓}[/tex]

hope it helps ~

Answer:

[tex] \qquad \quad \large \boxed{\bold{ \: \: Velocity = \green{21.36 \: m/s \: \: }}} \\ [/tex]

Explanation:

[tex] \sf{Given:}[/tex]

• A force of 16N acts on a body of mass 90 kg for 2 minutes.
• The body is initially at rest.

[tex] \sf{To \: Find:}[/tex]

• What is the final velocity?

[tex]\large\underline{\mathcal{\blue{SOLUTION:}}} \\ [/tex]

First, we have to find the acceleration of the body:

[tex] \sf{Given:}[/tex]

• [tex] \bold{Force \: (F) = \underline{16N}} \\ [/tex]
• [tex] \bold{Mass \: (m) = \underline{90 \: kg}} \\ [/tex]

According to the question by using the formula we get,

[tex]\begin{gathered}\implies \: \sf\boxed{\bold{ \: \: \: F =\: ma \: \: \: }}\\\end{gathered} [/tex]

[tex] \sf{where,} \\ [/tex]

• [tex] \bold{F = Force} \\ [/tex]
• [tex] \bold{m = Mass} \\ [/tex]
• [tex] \bold{a = Acceleration} \\ [/tex]

So, by putting those values we get,

[tex]\begin{gathered}\implies \: \sf 16 =\: 90a\\\end{gathered} [/tex]

[tex]\begin{gathered}\implies \: \sf \dfrac{16}{90} =\: a\\\end{gathered} [/tex]

[tex]\begin{gathered}\implies \: \sf 0.18 =\: a\\\end{gathered} [/tex]

[tex]\begin{gathered}\implies \: \sf\bold{a =\: 0.18\: m/s^2}\\\end{gathered} [/tex]

Hence, the acceleration of the body is 0.18 m/s² .

Now, we have to find the final velocity of the body:

[tex] \sf{Given:}[/tex]

• [tex] \bold{Initial \: Velocity \: (u) = \underline{ 0 \: m/s}} \\ [/tex]
• [tex] \bold{Acceleration \: (a) = \underline{0.18 \: m/s^2}} \\ [/tex]
• [tex] \begin{aligned}\bold{Time \: Taken \: (t) = \underline{\bold{ 2 \: minutes}}} \\ \bold{= \underline{\bold{(2 × 60) \: seconds}}} \\ \bold{ = \underline{\bold{120 \: seconds}}} \end{aligned} \\ [/tex]

According to the question by using the formula we get,

[tex]\begin{gathered}\implies \: \sf\boxed{\bold{v =\: u + at}}\\\end{gathered} [/tex]

[tex] \sf{where,}[/tex]

• [tex] \bold{v = Final \: Velocity} \\ [/tex]
• [tex] \bold{u = Initial \: Velocity} \\ [/tex]
• [tex] \bold{a = Acceleration} \\ [/tex]
• [tex] \bold{t = Time \: Taken} \\ [/tex]

So, by putting those values we get,

[tex]\begin{gathered}\implies \: \sf v =\: 0 + (0.18 \times 120)\\\end{gathered} [/tex]

[tex]\begin{gathered}\implies \: \sf v =\: 0 + 21.33\\\end{gathered} [/tex]

[tex]\begin{gathered}\implies \: \sf\bold{\underline{v =\: 21.36\: m/s}}\\\end{gathered} [/tex]

[tex] \large \sf{Thus,} \\ [/tex]

[tex]\\\qquad\color{yellow}{\bigstar}\\ \qquad\color{yellow}{\bigstar}-\:\boxed{\bold{\green{\pmb{ \: Velocity = \green{21.36 \: m/s \: }}}}}\: - \bigstar\\\qquad\color{yellow}{\bigstar} [/tex]

Answer:

Astigmatism

a also have those answer

Answer:

1. be kind to them.

2. always pray and always help other people.

Explanation:

Hope It Helps

Stay Safe And Healthy

God Bless

Answer:

mango simo

Explanation:

kay waay ka ga tuon