what part of the oven is the hottest​

Step-by-step explanation:

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[tex]\huge\mathfrak\purple{Direction:}[/tex]

Learning Task 2: Solve each problem using the application of LCM and GCF.

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[tex]\huge\mathfrak\purple{Problem:}[/tex]

In Art class, Mrs. Lucia had 36 sheets of green paper and 42 sheets if blue paper. If Mrs. Lucia wanted to give an equal number of each type of paper, how many sheets of paper should each pupil get?

[tex]\huge\mathfrak\purple{Solution:}[/tex]

Since the number of each pupil is not mentioned, let's find the highest possible number of sheets that Mrs. Lucia could give to each pupils. To solve the problem, we need to find the GCF using the factorization.

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Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36

Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42

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[tex] \bold {GCF} = { \boxed{ \bold{ \green{6}}}} \\ [/tex]

It means that 6 is the highest possible number of sheets that Mrs. Lucia could give to each pupils.

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Answer:

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Answer:

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Explanation:

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Standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients. x, y are the variables. c is the constant term. The values of x and y represent the coordinates of the point on the line.

1. a. y = 5x + 9 ; b. 5x - y + 9 = 0
2. a. y =  [tex]\frac{6}{-5}[/tex]× - [tex]\frac{2}{5}[/tex] ; b. 6x + 5y + 2 = 0
3. a. y = [tex]\frac{3}{4}[/tex]× + 4 ; b. 3x - 4y + 16 = 0
4. a. y = 2x + 6 ; b. 2x - y + 6 = 0
5. a. y = [tex]\frac{5}{6}[/tex]× - [tex]\frac{7}{6}[/tex] ; b. 5x - 6y - 7 = 0

1. m = 5 point (-1,4)

a. Find the y - intercept.

y = mx + b

4 = (5)(-1) + b

4 = -5 + b

4 + 5 = b

9 = b

Find the equation of the line.

y = mx + b

y = 5x + 9

b. Write the equation in standard form.

y = 5x + 9

-5x + y - 9 = 0

Remove the negative coefficient of x.

-1[-5x + y - 9 = 0]

5x - y + 9 = 0

2. (3, -4)(-2,2)

a. Find the slope.

m = [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]

m = [tex]\frac{2 - (-4)}{-2 - 3}[/tex]

m = [tex]\frac{2 + 4}{-5}[/tex]

m = [tex]\frac{6}{-5}[/tex]

Find the y - intercept.

y = mx + b

-4 = [tex]\frac{6}{-5}[/tex](3) + b

-4 = [tex]\frac{18}{-5}[/tex] + b

-4 + [tex]\frac{18}{5}[/tex] = b

[tex]\frac{-20}{5}[/tex] + [tex]\frac{18}{5}[/tex] = b

[tex]\frac{-2}{5}[/tex] = b

Find the equation of the line.

y = mx + b

y =  [tex]\frac{6}{-5}[/tex]× - [tex]\frac{2}{5}[/tex]

b. Write the equation in standard form.

y =  [tex]\frac{6}{-5}[/tex]× - [tex]\frac{2}{5}[/tex]

[tex]\frac{6}{5}[/tex]× + y + [tex]\frac{2}{5}[/tex] = 0

Remove the denominator.

5[[tex]\frac{6}{5}[/tex]× + y + [tex]\frac{2}{5}[/tex] = 0]

6x + 5y + 2 = 0

3. m = [tex]\frac{3}{4}[/tex] y- intercept = 4

a. Find the equation of the line.

y = mx + b

y = [tex]\frac{3}{4}[/tex]× + 4

b. Write the equation in standard form.

y = [tex]\frac{3}{4}[/tex]× + 4

- [tex]\frac{3}{4}[/tex]× + y - 4 = 0

Remove the denominator.

4[- [tex]\frac{3}{4}[/tex]× + y - 4 = 0]

-3x + 4y - 16 = 0

Remove the negative coefficient of x.

-1[-3x + 4y - 16 = 0]

3x - 4y + 16 = 0

4. x - intercept = -3 ; y - intercept = 6

(-3, 0)(0,6)

Find the slope.

m = [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]

m = [tex]\frac{6 - 0}{0 - (-3)}[/tex]

m = [tex]\frac{6}{3}[/tex]

m = 2

Find the equation of the line.

y = mx + b

y = 2x + 6

b. Write the equation in standard form.

y = 2x + 6

-2x + y - 6 = 0

Remove the negative coefficient of x.

-1[-2x + y - 6 = 0]

2x - y + 6 = 0

5. (-1,-2)(5,3)

Find the slope.

m = [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]

m = [tex]\frac{3 - (-2)}{5 - (-1)}[/tex]

m = [tex]\frac{3 + 2}{5 + 1}[/tex]

m = [tex]\frac{5}{6}[/tex]

Find the y - intercept.

y = mx + b

y = [tex]\frac{5}{6}[/tex]× + b

-2 = [tex]\frac{5}{6}[/tex](-1) + b

-2 = - [tex]\frac{5}{6}[/tex] + b

-2 + [tex]\frac{5}{6}[/tex] = b

- [tex]\frac{12}{6}[/tex] + [tex]\frac{5}{6}[/tex] = b

- [tex]\frac{7}{6}[/tex] = b

Find the equation of the line.

y = mx + b

y = [tex]\frac{5}{6}[/tex]× - [tex]\frac{7}{6}[/tex]

b. Write the equation in standard form.

y = [tex]\frac{5}{6}[/tex]× - [tex]\frac{7}{6}[/tex]

- [tex]\frac{5}{6}[/tex]× + y + [tex]\frac{7}{6}[/tex] = 0

Remove the denominator.

6[- [tex]\frac{5}{6}[/tex]× + y + [tex]\frac{7}{6}[/tex] = 0]

-5x + 6y + 7 = 0

Remove the negative coefficient of x.

-1[-5x + 6y + 7 = 0]

5x - 6y - 7 = 0

How to find the equation of the line: https://brainly.ph/question/6736797

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