Answer:
Solotion:
ARITHMETIC SEQUENCE:
Finding the THREE TERMS or 3 arithmetic means between 6 and 54:
Let a2, a3, and a4 be the three terms missing between 6 and 54:
This means that we have 5 terms but we don't know the 2nd 3rd and 4th terms.
First thing to do is find first the common difference (d)
That is,
a₅ = a₁ + (n-1)d
54 = 6 + (5-1)d
54 = 6 + 4d
54-6 = 4d
48/4 = 4d/4
d=12
So we substitute the known values:
a₂ = a₁ + 12
a₂ = 6 + 12
a₂ = 18
a₃ = a₂ +12
a₃ = 18 +12
a₃ = 30
a₄ = a₃ +12
a₄ = 30 +12
a₄ = 42
Therefore the sequence are 6, 18, 30 , 42 ,54.
Step-by-step explanation:
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