Evaluate (x+3)²+y²=4

Answers 1

Answer:

x = -3 - [tex]\sqrt{4-y^2}[/tex] or x = -3 + [tex]\sqrt{4-y^2}[/tex]

Step-by-step explanation:

solve [tex](x + 3) ^{2}[/tex] + [tex]y^{2}[/tex] = 4 x = -3 - [tex]\sqrt{4-y^2}[/tex] or x = -3 + [tex]\sqrt{4-y^2}[/tex]

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